8y^2-35y+12=0

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Solution for 8y^2-35y+12=0 equation: 



8y^2-35y+12=0

a = 8; b = -35; c = +12;
Δ = b2-4ac
Δ = -352-4·8·12
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-29}{2*8}=\frac{6}{16}
=3/8
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+29}{2*8}=\frac{64}{16}
=4
$

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